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&nbspA uniform rod of mass&nbspM&nbspand length&nbspL&nbspis pivoted at dis

     A uniform rod of mass M and length L is pivoted at distance x from its center and undergoes harmonic oscillations.M = 1.6 kgL = 1.5 mx = 0.21 mPart (a) In terms of M, L, and x, what is the rod’s moment of inertia I about the pivot point.Part (b) Calculate the rod’s period T in seconds for small oscillations about its pivot point.Part (c) In terms of L, Find an expression for the distance xm for which the period is a minimum.

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