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How do you factor ##x^3y^3 – 8##?

    ##=(xy-2)(x^2y^2+2xy+2)##

    ##x^3y^3-8##
    or
    ##(xy)^3-2^3##
    Since ##a^3-b^3=(a-b)(a^2+ab+b^2)##
    or
    ##=(xy-2)((xy)^2+2xy+2)##
    ##=(xy-2)(x^2y^2+2xy+2)##

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