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How do you convert ##y = x## into polar form?

    I found: ##tan(theta)=1##

    Consider the following diagram:

    We can see that the relationships between rectangular and are:
    ##r=sqrt(x^2+y^2)##
    ##theta=arctan(y/x)##
    and:
    ##x=rcos(theta)##
    ##y=rsin(theta)##
    Given our expression:
    ##y=x##
    you have:
    ##cancel(r)sin(theta)=cancel(r)cos(theta)##
    and write:
    ##tan(theta)=1##

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